[Blindmath] Graphing

Smith, Andrew smitha3 at students.rowan.edu
Tue Apr 15 22:31:55 UTC 2014


Hi Jacques,
The equation you have is:
x+5 = 0
So, subtract 5 from each side to get:
x = -5
You will have a vertical line as your graph.  Think about it: if x =
-5, then for all y, x = -5.  So, for instance, (-5, 0), (-5, 1), (-5,
2)...
X never changes, so that's where the vertical line comes from.
Cheers.

On 4/15/14, Emanuela Ughi <emanuela.ughi at gmail.com> wrote:
> It is vertical indeed. All its point have the same x=-5.
> Emanuela
>
>
> 2014-04-16 0:05 GMT+02:00 Jacques Chappell <jacqueschappell at comcast.net>:
>
>> I have the equasion x+5=0 and we are to graph this, but I am not sure
>> what
>> to do. I have a feeling this is a vertical line, although I could be
>> wrong.
>> Could I get some help? Thanks.
>>
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