[Blindmath] Division of Polynomials

Sat May 3 19:07:32 UTC 2014

We are working on dividing binomials into trinomials and 4-term polynomials.  He just lectured on adding in the missing term (if missing) with a placeholder term (zero coefficient).

-----Original Message-----
From: Blindmath [mailto:blindmath-bounces at nfbnet.org] On Behalf Of Bill Dengler
Sent: Saturday, May 03, 2014 11:55 AM
To: Blind Math list for those interested in mathematics
Subject: Re: [Blindmath] Division of Polynomials

Are you dividing a binomial 	by a monomial or a binomial by a binomial? If the former, than the long division thing need not apply.

Bill
On May 2, 2014, at 5:31 PM, Elise Berkley <bravaegf at hotmail.com> wrote:

> Thanks everyone.  I can actually do them in my head (the ones we are 
> solving now). But, if they get more difficult (which they will, with 
> me majoring in math), I will have to struggle through it.  Thanks, 
> Bill for that suggestion.  I'll try it, and if I don't get it, I'll 
> email you again.  Elise
> 
> -----Original Message-----
> From: Blindmath [mailto:blindmath-bounces at nfbnet.org] On Behalf Of 
> sabra1023
> Sent: Friday, May 02, 2014 11:30 AM
> To: Blind Math list for those interested in mathematics
> Subject: Re: [Blindmath] Division of Polynomials
> 
> There is a way to do it. Cited people just keep presenting things visually and can't think outside the box, no pun intended, to find another way to do it. I know someone who knows how to do it, but they haven't shown me yet. I just failed that section when I was in math before.
> 
>> On May 2, 2014, at 12:04 PM, Bill Dengler <codeofdusk at gmail.com> wrote:
>> 
>> Unfortunately, we never figured out a way for me to do these. My math 
>> teacher did, however, find a way for me to find the correct answer for these types of questions if they were multiple choice. For example, if the question was 3x^3-5x+2/x+2, you would multiply all the choices by x+2, and if you got 3x^3-5x+2 then that was the correct answer. As far as factoring them goes, though, I just used the quadratic formula, x=(-b±√(b^2-4ac))/2a I would take the solutions I got from the Quadratic Formula to generate the factors, a(x-x1)(x-x2). In other words, distribute the a term to the quantity x minus your first solution for your first factor, and your second factor is the quantity x minus the second solution.
>> Hope that helped you. If you need clarification feel free to email me on or off list.
>> Bill
>>> On May 2, 2014, at 12:45 AM, Elise Berkley <bravaegf at hotmail.com> wrote:
>>> 
>>> 
>>> 
>>> Hey, everyone!  My algebra instructor is working on division of polynomials.
>>> We are doing them in the long division manner (within the box).  I 
>>> understand the concept and it comes easy for me.  But, does anyone 
>>> have suggestions on how to read these problems in braille and 
>>> translate them on the computer for my homework.  I only use Word, 
>>> and I don't have any math-speaking programs.  Thanks for the help.  
>>> Elise
>>> 
>>> 
>>> 
>>> Elise Berkley
>>> 
>>> "The joy of the Lord is my strength."
>>> 
>>> 
>>> 
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