[BlindMath] I need help with vectors and electric field

[Abdulqadir Ahmad]

Hi Mr. Fine,

Thank you for replying to my message.

I think there was a mis understanding somewhere.

What the question is asking for is the electric field at point P and Q. 
Coulomb's law yields the force.

So, coulomb's law is F = {kQq} / r^2 right?

The formula for calculating electric field is: E = {kq} / r^2.

We can simplify coulomb's law like this: F = QE

The vector of interest here is E, not F, and F and E aren't the same.

The vector at point p for q_1 (first charge) will be: {8.99 * 10 ^ 9 * 
0.004} / {0.3 ^ 2}

 > On a side note, which one is better: 0.03 ^ 2 or {0.03} ^ 2 - 
emphasis on the braces.

Back to business. For point p, both vectors will be facing the same 
direction, so I can just add the magnitudes of either vectors to get the 
resultant vector right?

While for point q, the vectors E_1 and E_2 are facing different 
directions. E_1 is facing upwards, towards (+, +), while E_2 is facing 
downwards, towards (+, -). How can I add such vectors? Vectors with 
different directions, I.E. \theta_1 is not equal to \theta_2.

I hope my question is clearer now.

With kind regards,

Abdulqadir Ahmad