[BlindMath] Strange math / logic question
ckgoodwin85 at gmail.com
ckgoodwin85 at gmail.com
Sat Aug 17 07:10:49 UTC 2024
Hi Ken,
I'm going to reflect your problem statement back to you to see how well I've
understood it.
* You have a matrix, a square grid, where the cells get filled. So each
cell is either full or empty.
* Each row gets filled from left to right. Each row though may not get
completely filled.
* The last row is slightly different so it can be ignored for now.
* You want a measure of how full your matrix is
The obvious answer is just to work out the percentage of filled cells. So
if the matrix has 100 cells and 90 are full, then confidence level is 90%.
However, I suspect that I've missed out something from your problem
statement and it isn't as simple as this otherwise you wouldn't have asked
it smiley face
Can you explain the problem a bit more?
Best, Chris
-----Original Message-----
From: BlindMath <blindmath-bounces at nfbnet.org> On Behalf Of Ken Perry via
BlindMath
Sent: Saturday, August 17, 2024 1:46 AM
To: 'Blind Math list for those interested in mathematics'
<blindmath at nfbnet.org>
Cc: kperry at blinksoft.com
Subject: [BlindMath] Strange math / logic question
I have a strange math / logic problem. I think I could teach a neural net
to figure this out, but I am trying to produce a formula that would give me
a number that is bigger the more columns are used. An example would be I
have a 50 row and 20 column matrices of things. The matrix of things will
have things in the first column all the way up to the 50th column. If the
matrix is square and fills all the columns. ON all the rows.
. I want a confidence level close to 100 %
The less columns are used or the more ragged the right side is I.e., if One
or more random rows are missing 20 10 or 30 etc. then I want a much lower
confidence in fact in around 30 to 50. If a whole group is missing a lot of
columns, then again it should be exceptionally low number.
If the last row is short though I want the confidence level to still be
high. I could chop it off before calculating and then deciding on the last
row separately.
Does anyone have an easy method of I guess I would call it a fullness
factor right justified calculation function. Note it doesn't matter what I
stick in the column items I just want it as a count of things starting from
the left and a confidence factor the more ragged or less full the matrix is.
Note this is not a school thing it is a software Engineering question for
something I am working on.
I am writing this in python if you have a suggestion, a library, a formula .
Let me know.
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