[Blindmath] Factoring Question.

[GianniP46]

it was from a text book.  I think they had a typo.  the minus 1 at the end should have been a plus 1.
  ----- Original Message ----- 
  From: Jonathon Yaggie 
  To: Blind Math list for those interested in mathematics 
  Sent: Thursday, October 24, 2013 5:15 PM
  Subject: Re: [Blindmath] Factoring Question.


  if it is not a typo.  then the roots are the roots of x^2=-1-\sqrt{2} and
  x^2=-1+\sqrt{2} .  the first quadratic has imaginary solutions and the
  second has real solutions.  some one with a calculator could find the four
  roots - two imaginary and two real.


  On Thu, Oct 24, 2013 at 4:06 PM, Tami Jarvis <tami at poodlemutt.com> wrote:

  > Yeah, I keep thinking there may be something involving the imaginary
  > number i (the positive or negative square root of 1). It has been more
  > years than I care to admit, though, so I'm not getting anywhere trying to
  > use it to step through the equation to see if it works...
  >
  > The assumption that the equation is a typo makes it really easy, and it
  > all works out nice and neat. :)
  >
  > Tami
  >
  >
  > On 10/23/2013 09:21 PM, I. C. Bray wrote:
  >
  >>          Sorry, I misplaced / deleted the post I was replying to due to a
  >> phone call that interrupted my posting.
  >>
  >> To whom it was that asked the factoring question.
  >>
  >> That expression is unfactorable over the set of Real numbers.
  >> it has roots of:
  >> "Plus or Minus" the square root of (1+the square root of(2) )
  >>
  >> That is an Irrational number due to the square root of 2...
  >>
  >> you can say that it is Prime with respect to real numbers
  >> or that it's roots are irrational, and I believe even imaginary.
  >>
  >>
  >>
  >> Respectfully,
  >>
  >> Ian  C. Bray
  >>
  >>
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  >>
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  -- 
  Jon Yaggie
  UIC Mathematics
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