[Blindmath] Slope

[qubit]

I would avoid using decimal notation since one of the fractions is 2/3, 
which has a nonterminating decimal notation.
If you just go back to grade school arithmetic and multiply and divide to 
normalize the fractions, you end up with -5/2 over -5/12 which reduces to 1 
over 1/6 which is 6.
--le
----- Original Message ----- 
From: "Zachary N. Griego-Dreicer" <zdreicer at gmail.com>
To: "Blind Math list for those interested in mathematics" 
<blindmath at nfbnet.org>
Sent: Tuesday, April 15, 2014 5:17 PM
Subject: Re: [Blindmath] Slope


Hi. I would convert  the fractions to decimals or vice versa, and then try 
converting from there. Remember rise over run.

Sent from my iPhone 5S Using VoiceOver

> On Apr 15, 2014, at 16:04, "Jacques Chappell" 
> <jacqueschappell at comcast.net> wrote:
>
> I have two sets of points, they are (2 over 3, 1 over 2) and (1 over 
> 4, -2),
> I know how to find slope, but no matter what I do I cant get the same 
> slope
> the book gets. Can somebody help me?
>
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